X^2-72x+1196=0

Solution for X^2-72x+1196=0 equation:

X^2-72X+1196=0

a = 1; b = -72; c = +1196;
Δ = b2-4ac
Δ = -722-4·1·1196
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-20}{2*1}=\frac{52}{2}
=26
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+20}{2*1}=\frac{92}{2}
=46
$